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https://forthright48.com/sum-of-coprime-numbers-of-integer/?utm_source=rss&utm_medium=rss&utm_campaign=sum-of-coprime-numbers-of-integer learning never ends Tue, 05 Nov 2019 15:42:50 +0000 hourly 1 https://wordpress.org/?v=6.5.8 https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-162 Fri, 27 Sep 2019 09:16:19 +0000 https://forthright48.com/?p=596#comment-162 https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-161 Fri, 20 Sep 2019 20:27:40 +0000 https://forthright48.com/?p=596#comment-161 https://toph.co/p/life-of-phi]]> https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-143 Sat, 27 Apr 2019 22:17:33 +0000 https://forthright48.com/?p=596#comment-143 Sezan Ahmed. Added. Thanks for the problem link.]]> https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-142 Thu, 11 Apr 2019 19:04:57 +0000 https://forthright48.com/?p=596#comment-142 https://devskill.com/CodingProblems/ViewProblem/550 This is a nice problem on this theorem. Please write about Wilson’s theorem and Gaussian Generalization of Wilson’s theorem next time.]]> https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-141 Mon, 11 Mar 2019 08:15:55 +0000 https://forthright48.com/?p=596#comment-141 P] = 1 when P is true, and 0 otherwise.]]> https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-135 Wed, 02 Jan 2019 12:39:02 +0000 https://forthright48.com/?p=596#comment-135 Game Addicted. For n=4, the formula is (phi(n)/2) * n = (phi(4)/2) * 4 = (2/2) * 4 = 4. So the formula is correct.
You are right about n=4 not having any odd prime factor. My intention was to prove that phi(n) is always even. Seems like when n is a power of 2, the logic given does not work. But, it is obvious that phi(power of 2) will also be even. I will add the missing logic to the post. Thanks for pointing it out.]]> https://forthright48.com/sum-of-coprime-numbers-of-integer/#comment-134 Wed, 02 Jan 2019 11:37:36 +0000 https://forthright48.com/?p=596#comment-134 2=(2/2)2=2. Please,correct me if I understand anything wrong.]]>